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Find the surface area of the torus in Exercise 6.2.63.

$$

=4 \pi^{2} R r

$$

Applications of Integration

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this question asked us to find the surface area of the tourists in this given exercise. Okay, What we know is that we're going to essentially be rotating X squared plus y minus R squared is lower. Kiss our square about the X axis. Not what we know is the distance from the X axis to this point is big armistice are co sign of are variable. Therefore, what we know is that we're looking at the length of an arc given the rotation R d of our variable so looking from 0 to 2 pi remember, this is a full rotation. We have capital are lurking in our minds lurking r squared And then we know we have this This essentially the same things d backs deep data It's the same idea and this is equivalent to four pi squared capital are lower case R